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10x^2-58x+72=0
a = 10; b = -58; c = +72;
Δ = b2-4ac
Δ = -582-4·10·72
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-58)-22}{2*10}=\frac{36}{20} =1+4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-58)+22}{2*10}=\frac{80}{20} =4 $
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